(3x+2)(x+9)+(x-9)^2=0

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Solution for (3x+2)(x+9)+(x-9)^2=0 equation: 



(3x+2)(x+9)+(x-9)^2=0

We multiply parentheses ..

(+3x^2+27x+2x+18)+(x-9)^2=0

We get rid of parentheses

3x^2+27x+2x+(x-9)^2+18=0

We add all the numbers together, and all the variables

3x^2+29x+(x-9)^2+18=0

We move all terms containing x to the left, all other terms to the right

3x^2+29x+(x-9)^2=-18

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